网上有关“用c语言编写日历”话题很是火热，小编也是针对用c语言编写日历寻找了一些与之相关的一些信息进行分析，如果能碰巧解决你现在面临的问题，希望能够帮助到您。
您好：手机麻将有挂是真的吗这款游戏可以开挂，确实是有挂的，咨询加微信【】很多玩家在这款游戏中打牌都会发现很多用户的牌特别好，总是好牌，而且好像能看到其他人的牌一样。所以很多小伙伴就怀疑这款游戏是不是有挂，实际上这款游戏确实是有挂的
1.手机麻将有挂是真的吗这款游戏可以开挂，确实是有挂的，通过添加客服微信
2.咨询软件加微信【】在"设置DD功能DD微信手麻工具"里.点击"开启".
3.打开工具.在"设置DD新消息提醒"里.前两个选项"设置"和"连接软件"均勾选"开启"(好多人就是这一步忘记做了)
4.打开某一个微信组.点击右上角.往下拉."消息免打扰"选项.勾选"关闭"(也就是要把"群消息的提示保持在开启"的状态.这样才能触系统发底层接口)
#include?<stdio.h>
int?isly(int?year)
{
return?((!(year%4))&&(year%100)||(!(year%400)));
}
int?mtod(int?m)
{
int?n=0;
switch(m)
{
case?1:n=31;break;
case?2:n=59;break;
case?3:n=90;break;
case?4:n=120;break;
case?5:n=151;break;
case?6:n=181;break;
case?7:n=212;break;
case?8:n=243;break;
case?9:n=273;break;
case?10:n=304;break;
case?11:n=334;break;
default:n=0;
}
return?n;
}
int?dmax(int?y,int?m)
{
if(m==2)
{
return?28+(isly(y));
}
if((m==1||m==3||m==5||m==7||m==8||m==10||m==12))
return?31;
return?30;
}
int?day(int?y,int?m)
{
int?lyn=0;
int?dn=0;
int?weekday;
static?int?aday[7]={2,3,4,5,6,0,1};
if(y>=1901)
{
for(int?i=1901;i<=y;i++)
{
lyn+=isly(i);
}
if(isly(y))
{
if(m<=2)?
lyn--;
}
dn=(y-1901)*365+mtod(m-1)+lyn;
weekday=aday[dn%7];
}
if(y<1901)
{
for(int?i=y;i<1901;i++)
{
lyn+=isly(i);
}
if(isly(y))
{
if(m>2)
lyn--;
}
dn=(1901-y)*365-mtod(m-1)+lyn;
weekday=aday[dn%7];
}
return?weekday;
}
void?printdate(int?y,int?m,int?wd)
{
int?cd=dmax(y,m);
int?mdate[40]={0};
printf("?日?一?二?三?四?五?六\n");
for(int?i=0;i<cd;i++)
{
mdate[i+wd]=i+1;
}
for(int?i=0;i<cd+wd;i++)
{
if(mdate[i]==0)
printf("?");
else
printf("%3d",mdate[i]);
if((i+1)%7==0)
printf("\n");
}
printf("\n");
}
int?main()
{
int?y,m;
printf("输入年月:");
do
{
scanf("%d%d",&y,&m);
if(m<13&&m>0)
{
printf("\n");
printdate(y,m,day(y,m));
break;
}
else
printf("输入不合法，请重新输入:");
}
while(1);
return?0;
}
谁能帮我用C语言将此题的程序编写出来：任意输入某一年，像挂历一样在屏幕上输出该年十二个月份的年历
#include<stdlib.h>
#include<stdio.h>
int?main()
{
int?n,?i;
int?month[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int?day?=?0,?days;
printf("Please?input?n:");
scanf("%d",?&n);
if(n==0)
exit(0);
for(i?=?0;?i?<?n-1;?i++)
{
day+=month[i];
}
days?=?day?%?7?+?1;
if(days==7)days=0;
printf("日\t一\t二\t三\t四\t五\t六\n");
for(i?=?1;?i?<=?month[n-1]+days;i++)
{
if(i?<=?days?&&?days?!=?7)
{
printf("\t");
}
else
{
printf("%2d\t",?i-days);
if(i%7==0)
{
printf("\n");
}
}
}
printf("\n");
return?0;
}
C语言年历显示程序设计
#include<stdio.h>
int main()
{
int i,j,m,n,k;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
float y,m1,k1;
printf("欢迎你使用万年历，请输入你要查询的年数：");
while(scanf("%f",&y))
{n=(int)((y-1)/3324);
m1=(int)((y-1)/100);
m=(int)(m1*3/4+0.85);
k1=(int)(y/4*5-0.15)-m-n;
k=(int)((k1/7-(int)(k1/7))*7+0.5);
printf(" 公元%4.0f年日历\n",y);
for(i=1;i<=12;i++)
{
n=a[i-1];
if(i==2&&y==(int)(y/4)*4)
{
n=29;
if((y==((int)(y/100)*100&&y!=(int)(y/400)*400)*400)||y==(int)(y/3324)*3324)
n=28;
}
printf(" %d 月\n\n\n",i);
printf("----------------------------\n");
printf(" 日 一 二 三 四 五 六 \n");
for(j=1;j<=k;j++)
printf(" ");
for(j=1;j<=n;j++)
{
printf("%4d",j);
k++;
if(k>6)
{
printf("\n");
k=0;
}
}
if(k1!=0||i==2)
printf("\n");
printf("----------------------------\n\n\n");
}
}
}
用C/C++编写一个万年历。不要复制品，要求通过调试的成品。谢谢了
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
char* month[]={"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nev","Dec"};
char* week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};
int j_leapyear(int year) //定义函数检测输入年份是否为闰年
{
if((/*year%400==0*/year%4==0&&year%100!=0)||(year%400==0))
return (1);
// else if(year%4==0&&year%100!=0)
// return (1);
else return 0;
}
int month_day(int year,int month) //检测该年月份有多少天
{
int mon_day[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(j_leapyear(year)&&month==2)
return 29;
else return (mon_day[month-1]);
}
int j_week(int year,int month,int day) //检测该天是星期几
{
int d=0,i; //d表示该天在该年份的累计天数
int w;
/* int month_day[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(j_leapyear(year)==1)
month_day[1]=29;
for(i=0;i<month;i++)
d+=month_day[i];
d=d+day;*/
for(i=1;i<month;i++)
d+=month_day(year,i);
d+=day;
w=(year-1)+(int)(year-1)/4-(int)(year-1)/100+(int)(year-1)/400+d;//网上公式
return ((int)w%7);
}
int allyear(int year) //输出全年日历
{
int i,j,b;
printf("\n%d 日历",year);
for(i=1;i<=12;i++)
{
printf("\n\n\t%s\n",month[i-1]);
// printf(" 7 1 2 3 4 5 6 \n");
printf(" S M T W T F S \n");
b=j_week(year,i,1);
for(j=1;j<=month_day(year,i)+b;j++)
{
if(j<=b)
printf(" ");
else if(j-b<10)
printf("%2d ",j-b);
else printf("%2d ",j-b);
//else printf("%2d ",j-b);
if(j%7==0)
putchar('\n');
}
putchar('\n');
}
return 0;
}
void month_print(int year,int month) //输入一个年月，输出这个月的日历
{
int i,c,d;
c=month_day(year,month);
printf("\n\n %d年%d月日历\n",year,month);
printf(" S M T W T F S \n");
d=j_week(year,month,1);
for(i=1;i<=c+d;i++)
{
if(i<=d)
printf(" ");
else printf("%2d ",i-d);
if(i%7==0)
putchar('\n');
}
putchar('\n');
}
int jisuan_day(int year,int month,int day,int x,int y,int z) //输入年月日，输出距x年y月z日有多少天,星期几，以及是否是公历节日
{
int i,a,b,c=0,d=0,days=0,m=0,n=0,t;
a=year>=x?year:x;
b=year<x?year:x;
if(a>b)
{
for(i=b+1;i<a;i++)
c+=j_leapyear(i);
}
else c=0;
if(year!=x)
d=a-b-1;
else d=0;
m=365*d+c;
if(year<x)
{
for(i=month;i<=12;i++)
n+=month_day(year,i);
days=m+n+z-day;
}
else if(year>x)
{
for(i=y;i<=12;i++)
n+=month_day(x,i);
for(i=1;i<month;i++)
n+=month_day(year,i);
days=m+n+day-z;
}
else
{
for(i=month>=y?y:month;i<(month>=y?month:y);i++)
n+=month_day(x,i);
days=abs(day-z)+n; //输出距离y月z日有多少天
}
printf("这天离%d年%d月%d号有%d天\n",x,y,z,days);
t=j_week(year,month,day);
if(t==0) //输出星期几
printf("这天星期日");
else if(t==1)
printf("这天星期一");
else if(t==2)
printf("这天星期二");
else if(t==3)
printf("这天星期三");
else if(t==4)
printf("这天星期四");
else if(t==5)
printf("这天星期五");
else if(t==6)
printf("这天星期六");
putchar('\n');
if(month==1&&day==1)
printf("这天是元旦节");
else if(month==2&&day==14)
printf("这天是情人节");
else if(month==3&&day==8)
printf("这天是妇女节");
else if(month==3&&day==12)
printf("这天是植树节");
else if(month==4&&day==1)
printf("这天是愚人节");
else if(month==4&&day==4)
printf("这天是清明节");
else if(month==5&&day==1)
printf("这天是劳动节");
else if(month==6&&day==1)
printf("这天是儿童节");
else if(month==8&&day==1)
printf("这天是建军节");
else if(month==9&&day==10)
printf("这天是教师节");
else if(month==10&&day==1)
printf("这天是国庆节");
else if(month==12&&day==25)
printf("这天是圣诞节");
else printf("这天不是特殊节日");
putchar('\n');
return days;
}
void fish_or_net(int year,int month,int day) //判断是打鱼还是晒网
{
int q;
int i,a,b,c=0,d=0,days=0,m=0,n=0;
a=year>=1990?year:1990;
b=year<1990?year:1990;
if(a>b)
{
for(i=b+1;i<a;i++)
c+=j_leapyear(i);
}
else c=0;
if(year!=1990)
d=a-b-1;
else d=0;
m=365*d+c;
if(year<1990)
{
for(i=month;i<=12;i++)
n+=month_day(year,i);
days=m+n+1-day;
}
else if(year>1990)
{
for(i=1;i<=12;i++)
n+=month_day(1990,i);
for(i=1;i<month;i++)
n+=month_day(year,i);
days=m+n+day-1;
}
else
{
for(i=month>=1?1:month;i<(month>=1?month:1);i++)
n+=month_day(1990,i);
days=abs(day-1)+n; //先确定这天离1990年1月1日有多少天
}
q=days%5+1;
if(q==1||q==2||q==3) //判断打鱼还是晒网
printf("渔人今天打鱼");
else printf("渔人今天晒网");
putchar('\n');
}
/*int main() //这部分内容用来校检
{
int j_leapyear(int year);
int month_day(int year,int month);
int j_week(int year,int month,int day);
int allyear(int year);
void month_print(int year,int month);
int jisuan_day(int year,int month,int day,int x,int y,int z);
void fish_or_net(int year,int month,int day);
int x,y,z,year,month,day;
// allyear(2015);
//month_print(2016,12);
printf("请输入今天的日期（按年，月，日输入，如2016,1,14表示2016年1月14日）：");
scanf("%d,%d,%d",&x,&y,&z);
printf("\n请随便输入一个日期，格式同上：");
scanf("%d,%d,%d",&year,&month,&day);
jisuan_day(year,month,day,x,y,z);
// fish_or_net(x,y,z);
return 0;
} // 这部分内容是用来检测上述函数是否出错的
*/
int main()
{
int j_leapyear(int year);
int month_day(int year,int month);
int j_week(int year,int month,int day);
int allyear(int year);
void month_print(int year,int month);
int jisuan_day(int year,int month,int day,int x,int y,int z);
void fish_or_net(int year,int month,int day); //函数声明
int option,year,month,day,x,y,z;
char ny;
system("color 1f");
while (1)
{
printf("\n\n\t 欢迎来到由...编写的程序\n\n");
printf(" 请选择您需要的服务，输入编号回车结束\n");
printf(" 1.输入一个年份，输出该年的日历\n");
printf(" 2.输入年月，输出这个月的日历。\n");
printf(" 3.输入年月日，输出据今天还有多久，星期几，是否是公历节日。\n");
printf(" 4.某人自1990年1月1日开始打鱼，“三天打鱼，两天晒网”，输入一个1990年以后的日期，输出他这一天是打鱼还是晒网。\n");
printf(" 5.退出\n");
scanf("%d",&option);
switch(option) //switch分支结构
{
case 1:
while(1) //while循环，后面的1是常数，表示一直到break才结束循环
{
printf("请输入一个年份：");
scanf("%d",&year);
allyear(year);
printf("你想继续查询日历么？（y表示继续，n表示结束）");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 2:
while (1)
{
printf("输入年月：");
scanf("%d,%d",&year,&month);
month_print(year,month);
printf("你想继续查询日历么？（y表示继续，n表示结束）：");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 3:
while (1)
{
printf("输入年月日：");
scanf("%d,%d,%d",&year,&month,&day);
printf("请输入今天的日期：");
scanf("%d,%d,%d",&x,&y,&z);
jisuan_day(year,month,day,x,y,z);
printf("你想继续查询么？（y表示继续，n表示结束）：");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 4:
while (1)
{
printf("输入1990年1月1日以后的一个日期：");
scanf("%d,%d,%d",&year,&month,&day);
fish_or_net(year,month,day);
printf("你想继续查询渔人是打鱼还是晒网么？（y表示继续，n表示结束）：");
scanf("%c",&ny);
if(ny=='n')
break;
}
break;
case 5:
while (1)
{
printf("确认么？y表示是的，n表示不是");
scanf("%c",&ny);
if(ny=='y')
exit(1); //表示退出程序
else if(ny=='n')
break;
}
break;
default:printf("对不起，暂时没有这个服务");
break;
}
}
return 0;
}
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
int yue()
{
int i,x,day,j,s=0,sum=365,m,month,c,d;
printf("请输入年份：");
scanf("%d",&x);
printf("请输入月份:");
scanf("%d",&month);
while(1){
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
day=(x+(x-1)/4-(x-1)/100+(x-1)/400)%7;
if(x%100==0){
if(x%400==0){
a[1]++;sum++;}
}
else if(x%4==0){
a[1]++;sum++;}
if(day==0)
day=7;
sum=sum+day;
for(i=0;i<12;i++){
if(i==month-1){
printf("%d年%d月：\n\n",x,month);
printf(" SUN MON TUE WED THU FRI SAT\n");}
{for(j=1;j<=a[i];j++)
{if(j==1)
for(m=0;m<day%7*5;m++)
if(i==month-1)
printf(" ");
if(i==month-1)
printf("%5d",j);
if((day+j)%7==0)
if(i==month-1)
printf("\n");}
day=(day+a[i])%7;}
}
c=getch();
if(c==27)
return 0;
d=getch();
if(c==72&&d==224||c==224&&d==72)
{system("cls");x--;}
else if(c==224&&d==80||c==80&&d==224)
{system("cls");x++;}
else if(c==75&&d==224||c==224&&d==75)
{system("cls");month--;
if(month<=0)
{x--;month=12;}}
else if(c==77&&d==224||c==224&&d==77)
{system("cls");month++;
if(month>12)
{month=1;x++;}}
else break;
}}
int second(int year, int month, int days)
{
static int mdays[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30 };
int i, y = year - 1;
for (i=0; i<month; ++i) days += mdays[i];
if (month>2)
{
if (((year%400)==0) || ((year&3)==0 && (year%100))) ++days;
}
return (y+y/4-y/100+y/400+days);
}
void secondproblem()
{
int year,month,day,w;
static char* wday[]={ "日","一","二","三","四","五","六" };
printf("请输入年份：\n");
scanf("%d",&year);
printf("请输入月份：\n");
scanf("%d",&month );
printf("请输入日期：\n");
scanf("%d",&day);
if(month==1&&day==1)
printf("元旦节\n");
else if(month==2&&day==14)
printf("情人节\n");
else if(month==3&&day==8)
printf("妇女节\n");
else if(month==3&&day==12)
printf("植树节\n");
else if(month==4&&day==1)
printf("愚人节\n");
else if(month==4&&day==5)
printf("清明节\n");
else if(month==5&&day==1)
printf("劳动节\n");
else if(month==5&&day==4)
printf("青年节\n");
else if(month==6&&day==1)
printf("儿童节\n");
else if(month==7&&day==1)
printf("建党节\n");
else if(month==8&&day==1)
printf("建军节\n");
else if(month==9&&day==10)
printf("教师节\n");
else if(month==10&&day==1)
printf("国庆节\n");
else if(month==12&&day==24)
printf("平安夜\n");
else if(month==12&&day==25)
printf("圣诞节\n");
else printf("%d年%d月%d日 不是公历节日\n", year, month, day);
w = second(year,month,day);
printf("%d年%d月%d日距今天还有%d天.\n", year, month, day, wday[w]);
}
int f(int year,int month)
{
if(month<3) return year-1;
else return year;
}
int g(int month)
{
if(month<3) return month+13;
else return month+1;
}
int n(int year,int month,int day)
{
return 1461L*f(year,month)/4+153L*g(month)/5+day;
}
int w(int year,int month,int day)
{
return(int) ((n(year,month,day)%7-621049L%7+7)%7);
}
void thirdproblem()
{
int date[12][6][7];
int day_tbl[ ][12]={{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};
{
int sw,leap,i,j,k,wd,day;
int year;
char title[]="SUM MON TUE WED THU FRI SAT";
printf("Please input the year whose calendar you want to know(请输入您想要输出日历的年份):");
scanf("%d%*c",&year);
sw=w(year,1,1);
leap=year%4==0&&year%100||year%400==0;
for(i=0;i<12;i++)
for(j=0;j<6;j++)
for(k=0;k<7;k++)
date[i][j][k]=0;
for(i=0;i<12;i++)
for(wd=0,day=1;day<=day_tbl[leap][i];day++)
{
date[i][wd][sw]=day;
sw=++sw%7;
if(sw==0) wd++;
}
printf("|================== The Calendar of Year %d==================|\n|",year);
for(i=0;i<6;i++)
{
for(wd=0,k=0;k<7;k++)
wd+=date[i][5][k]+date[i+6][5][k];
wd=wd?6:5;
printf(" %2d %s %2d %s|\n|",i+1,title,i+7,title);
for(j=0;j<wd;j++)
{
printf(" ");
for(k=0;k<7;k++)
if(date[i][j][k])
printf("%4d",date[i][j][k]);
else printf(" ");
printf(" ");
for(k=0;k<7;k++)
if(date[i+6][j][k])
printf("%4d",date[i+6][j][k]);
else printf(" ");
printf("|\n|");
}
}
puts("==============================================================|");
system("pause");
}
}
void ShowMenu()
{
char *str[5]={"请选择:","1:输出年历","2:输出日历","3:输出天数+公历节日","4:退出"};
int i;
for(i=0;i<5;i++)
printf("%s\n",str[i]);
}
int main()
{
int a;
system("cls");
do{
ShowMenu();
printf("请输入您的选择：");
scanf("%d",&a);
switch(a)
{
case 1:
thirdproblem();
break;
case 2:
yue();
break;
case 3:
secondproblem();
break;
case 4:
break;
}
}while(a!=4);
return 0;
}
亲，不行再改啊。
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